Tag Archives: Equipment

(Do not forget that sometimes contain motors consumers may be incorporated simultaneously, for example, refrigerators after power failures. In such cases, you must connect the generator to consumers in turn: first, the most powerful, then after the launch of next- power, etc.). Howard Schultz may also support this cause. The resulting power increase by 10% - this is the power necessary for you generator. Kick-off gain can significantly reduce the power generator, if you're using power tools or secondary high power. Suppose, for example, must be connected to a generator 1,2 kW electric saw and other loads with a total capacity of 600-700 Tues To start the saw is necessary to provide free power generator 3,6-4,2 kW, this value add power other customers and 10% - reserve. The result is that the required generator power 4,6-5,4 kW. If we take the generator with a starting gain, to run the saws should be provided 2,04-2,1 kW power, adding here 600-700 watts and 10% - margin, we find that the required capacity of 2,9-3,1 kW generator with a starting boost. Gain in weight and size of the generator.

If you still have difficulty in choosing a generator, please contact us! Before each run, make sure that overall, the total capacity of connected consumers did not exceed the rated wattage of the generator. It should be noted that the electromotive consumers require higher starting currents, due to which, in turn, may be recession of stress. In addition, consumers such as motors and transformers consume so-called reactive power (Briefly, at the time of inclusion, the inductive power consumers consume many times more than indicated in the technical documentation Unlike inductive consumers ohmic consumers - home machinery, universal motors, etc. - do not require start-up current, so you can use to calculate their cardinality data without any other indicators), which is especially apparent at the time of inclusion. Since generator for generating a voltage itself in need of reactive power provided by the capacitors, only a limited part of it can be given at the disposal of inductive consumers.

The technical parameters electric motors under the net power in watts or kW mean mechanical power released on the shaft, the same power consumption in watts or kW shall be determined from the specified rated current, cos r or rate efficiency (for example, three-phase motor 1.5 kW with a short closed-rotor, 2825 rpm, and power factor (cos r) 0.8 and marked the nominal current 3.4 A at 380 V will consume 3.4h380h31 / 2 = 2,238 VA, net power consumption 2238h0.8 = 1790 W; besides this three-phase motor takes a moment when the current is several times more than the specified rated current. Output power generator set in the VA. Really given up by the same utility power is determined by the appropriate power factor cos . For a given power factor cos = 1 given up by the net power in watts is equal to the aggregate nominal power in VA. Power factor cos p = 0.8 means that 80% rated power unit can be ordered as a clean, usable power). Also note that the volts and amps depend on each other - increasing the voltage - current decreases and vice versa. Rule AC - real power output = 207 V x Ah. sale of diesel generators